Question 360571
{{{6x^4 + 11x^2 +4 = 0}}}
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{{{x^2 = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x^2 = (-11 +- sqrt( 11^2-4*6*4 ))/(2*6) }}}
{{{x^2 = (-11 +- sqrt( 121-96 ))/(12) }}}
{{{x^2 = (-11 +- sqrt( 25 ))/(12) }}}
{{{x^2 = (-11 +- 5)/(12) }}}
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{{{(x[1])^2=-16/12=-4/3}}} 
{{{x[1]=0 +- (2/sqrt(3))i}}}
{{{highlight(x[1]=0 +- (2/3)sqrt(3)i)}}}
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{{{(x[2])^2=-6/12=-1/2}}} 
{{{highlight(x[2]=0 +- (sqrt(2)/2)i)}}}