Question 360547
{{{x^2-16x+15=0}}}
{{{(x^2-16x+64)+15=64}}}
{{{(x-8)^2+15=64}}}
{{{(x-8)^2=49}}}
{{{x-8= 0 +- 7}}}
{{{x=8 +- 7}}}
{{{highlight(x[1]=15)}}} and {{{highlight(x[2]=1)}}}