Question 360579
x(1/2) + (sqrt 3)x(1/4) - 18 = 0
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Let w = x^(1/4)
Then w^2 = x^(1/2)
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Substitute to get:
w^2 + sqrt(3)w - 18 = 0
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Quadratic Formula:
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w = [-sqrt(3) +- sqrt(3-4*-18)]/2
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w = [-sqrt(3) +- sqrt(75)]/2
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w = [-sqrt(3)+-5sqrt(3)]/2
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w = [-3sqrt(3)] or w = 2sqrt(3)
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Now, solve for "x" using Let w = x^(1/4)
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Solve: -3sqrt(3) = x^(1/4)
x = [-3sqrt(3)]^4 = 81*9 = 729
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Solve: 2sqrt(3) = x^(1/4)
x = [2sqrt(3)]^4 = 16*9 = 144
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Check these answers in the original equation:
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Cheers,
Stan H.