Question 360524
[(17a^2b^3)/(18yx)]/[(34a^2)/(9xy)] invert the second fraction & multiply.
(17a^2b^3)/(18xy)*(9xy)/(34a^2) cancel like terms.
----------------------
17a^2b^3/34a^2=b^3/2
-----------------------
9xy/18xy=1/2
----------------------
b^3/2*1/2=b^3/4 ans.