Question 360535
<pre><b>

You have it right.  There are two ways to go from the next to the last step:

{{{(3x^(-9)5x^5)/(18x^(-4))}}}

{{{(3*5x^(-4))/(18x^(-4))}}}

{{{(15x^(-4))/(18x^(-4))}}}

As I said above, there are two ways you can go from here.
You subtracted exponents and got

{{{(15x^0)/18}}}

and then replaced the {{{x^0}}} by {{{1}}},

{{{(15(1))/18}}}

{{{15/18}}}

which reduces to {{{5/6}}}

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The other way to go from

{{{(15x^(-4))/(18x^(-4))}}}

is to cancel the {{{x^(-4)}}}'s

{{{(15cross(x^(-4)))/(18cross(x^(-4)))}}}

and get {{{15/18}}} which reduces to {{{5/6}}}

Edwin</pre>