Question 360530
3y^2 + y - 4=0
Factor:
(3y+4)(y-1) = 0
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y = [-4/3] or y = 1
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2a^2 = 11a - 12
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2a^2 - 11a + 12 = 0
2a^2-8a-3a+12 = 0
2a(a-4)-3(a-4) = 0
(a-4)(2a-3) = 0
a = 4 or a = 3/2
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3j(j-2)=2(2-j)

3j(j-2) + 2(j-2) = 0
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(j-2)(3j+2) = 0
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j = 2 or j = -2/3
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Cheers,
St