Question 40310
Urn1: 4W & 2B
Urn2: 6W & 5B
P1 = P(Urn1 -> Black ball) (P1 is the probability that urn1 will give a black ball)
P2 = P(Urn2 -> Black ball) (P2 is the probability that urn2 will give a black ball)
P = P1 * P2 (P is the probability that both balls will be black)
Now,
In urn1, there are 6 balls in total, with 2 of them black, So,
P1 = 2/6
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In urn2 there are 11 balls in total, with 5 of them black, So,
P2 = 5/11
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P = P1 * P2
P = (2/6) * (5/11)
P = 10/66
Ans: P = 5/33
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