Question 360212
find the perimeter of an right angled traingle with an area 54 square meters and length of one leg is 12 meters?
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area = 54 m^2
one leg = 12
1/2 * 12 * L= 54
2*54/12=L
L=9 m
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hypotenuse = sqrt(9^2+12^2)
hypotenuse = sqrt(81+144)
= sqrt 169
=13.
the sides are 9,12,13
add up to get the perimeter
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m.ananth@hotmail.ca