Question 360198
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Let *[tex \Large x] represent the number of boxes of wrenches.  Then, since there are a total of 40 boxes of tools, the number of boxes of hammers has to be *[tex \Large 40\ -\ x].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 100x\ +\ 300(40\ -\ x)\ =\ 8400]


Do yourself a favor and simplify your arithmetic:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 3(40\ -\ x)\ =\ 84]


Solve for *[tex \Large x] and then compute *[tex \Large 40\ -\ x]


And the answer to your other question is yes.  Go to the Algebra.com home page.  Then use the little Google Search box and search for some key words in your problem.  You will have to do a little digging, but you will get there.  The probability that your problem (or one so close to it that the difference is barely noticable) has NOT been done already is miniscule.  We've seen them all (or very nearly so).


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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