Question 360158
<font face="Garamond" size="+2">


Let *[tex \Large x] represent the amount of 23% solution.  Then *[tex \Large 140\ -\ x] represents the amount of 65% solution.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.23x] ml


represents the amount of pure whatever it is that is contained in the 23% solution.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.65(140\ -\ x)] ml


represents the amount of pure whatever in the 65% solution.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.35(140)\ =\ 49] ml


represents the amount of pure whatever in the resulting 140 ml of 35% solution, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.23x\ +\ 0.65(140\ -\ x)\ =\ 49]


Solve for *[tex \Large x].  Then compute *[tex \Large 140\ -\ x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>