Question 5088
{{{x^2 + 16x + 25 = 0}}}  Use the quadratic formula {{{x= (-b+-sqrt (b^2 -4ac))/(2a)}}}, where a = 1, b= 16, and c=25.


{{{x= (-16+-sqrt (16^2 -4*1*25))/(2*1)}}}
{{{x= (-16+-sqrt (256 -100))/2}}}
{{{x= (-16+-sqrt (4)* sqrt (39))/2}}}
{{{x= (-16+- 2*sqrt (39))/2}}}


Factor out the 2:
{{{x= (2(-8+-sqrt (39)))/2}}}


Divide out the 2:
{{{x= (-8+-sqrt (39)) }}}


R^2 at SCC