<PRE><B>Question 360173</B>
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I don&#39;t know what inte &lt;i&gt;&lt;b&gt;r&lt;/b&gt;&lt;/i&gt; gers are, consecutive or otherwise, or how you would find a sum of them.  On the other hand, if you have two consecutive &lt;i&gt;&lt;b&gt;integers&lt;/b&gt;&lt;/i&gt;, then proceed as follows:


Let *[tex \Large x] represent the first (smaller) of the two integers.  Then *[tex \Large x\ +\ 1] must represent the second of the two integers because they are consecutive (look up the definition of &quot;consecutive&quot; if you don&#39;t understand why).  Then you can take their sum:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 1\ =\ 91]


Solve for *[tex \Large x] and then compute *[tex \Large x\ +\ 1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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