Question 359965
Complete the square to put the equation into vertex form, {{{y=a(x-h)^2+k}}} where ({{{h}}},{{{k}}}) is the vertex.
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{{{f(x)=x^2-12x+12}}}
{{{f(x)=(x^2-12x+36)+12-36}}}
 {{{highlight(f(x)=(x-6)^2-24)}}}
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({{{h}}},{{{k}}})=({{{6}}},{{{-24}}})
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{{{drawing(300,300,-2,12,-25,5,grid(1),circle(6,-24,0.3),blue(line(6,-220,6,220)),graph(300,300,-2,12,-25,5,x^2-12x+12,(x-6)^2-24)))}}}