Question 40285
The length of a picture is 1 inch less than twice its width.  The frame around the picture has a uniform width of 2 inches and an area of 96 square inches.  What are the dimensions of the picture?

OUTSIDE FRAME DATA:
Let the width be "x"
Then the length is "2x-1" inches.

PICTURE DATA:
width = x-2(2)=x-4 inches
length = 2x-1-2(2)= 2x-5 inches
EQUATION:
Picture area = length * width = 96 sq. in.
(x-4)(2x-5)=96
2x^2-13x+20=96
2x^2-13x-76=0
*[invoke quadratic "x",2,-13,-76]
Only x=10.22 is a usuable answer.
So, dimensions of the picture are:
width = x-2=8.22 inches
length = 2x-5=15.44 inches
cheers,
Stan H.