Question 359906
find four consecutive even interges such that the sum of the first three is two more than twice the fourth
..
let the four consequtive numbers be 
x,x+2,x+4,x+6
...
x+x+2+x+4=2(x+6)+2
3x+6=2x+12+2
3x+6=2x+14
3x-2x=14-6
x=8
8,10,12,14
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