<PRE><B>Question 359623</B>
A Car travels 240 mi. A second car, traveling 12 mph faster than the first,
 makes the same trip in 1 hour less time. Find the speed of each car
:
Let s = speed of the slower car
then
(s+12) = speed of the faster
:
Write a time equation; time = dist/speed
:
Slow car time - fast car time = 1 hr
{{{240/s}}} - {{{240/((s+12))}}} = 1
:
Multiply by s(s+12), results
240(s+12) - 240s = s(s+12)
:
240s + 2880 - 240s = s^2 + 12s
Combine as a quadratic equation on the right
0 = s^2 + 12s - 2880
Factors to
(s+60)(s-48) = 0
positive solution
s = 48 mph is the speed of the slower car
then
48 + 12 = 60 mph is the faster car
:
Check solution by finding the times of each 
{{{240/48}}} - {{{240/60}}} = 
 5 - 4 = 1 hr; confirms our solutions</PRE>