Question 359810
"Find 3 consecutive odd integers such that the first is 23 less than the sum of the second and third" means that {{{x=(x+2)+(x+4)-23}}}



{{{x=(x+2)+(x+4)-23}}} Start with the given equation.



{{{x=2x-17}}} Combine like terms on the right side.



{{{x-2x=-17}}} Subtract {{{2x}}} from both sides.



{{{-x=-17}}} Combine like terms on the left side.



{{{x=(-17)/(-1)}}} Divide both sides by {{{-1}}} to isolate {{{x}}}.



{{{x=17}}} Reduce.



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Answer:


So the solution is {{{x=17}}} 



This means that the 3 numbers are: 17, 19, 21



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Jim