Question 359390
1.Two good parts are selected.
{{{P(G,G)=14/33}}} , Correct!
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2.Two defective parts are selected. 
{{{P(D,D)=1/11}}}, Correct!
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3.1st good, 2nd defective.
{{{P(G,D)=8/33}}}, Correct!
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Exactly one defective part out of the two is selected.
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You already have half of the answer ({{{P(G,D)=8/33}}}). 
What about if you choose a defective part first, then a good part.
That would give you {{{P(D,G)}}}
P(exactly 1)={{{P(D,G)+P(G,D)}}}
P(exactly 1)={{{P(D,G)+8/33}}}
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Also,remember there are only 4 choices you can make, picking two parts.
GG-{{{P(G,G)=14/33}}}
DD-{{{P(D,D)=1/11}}}
GD-{{{P(G,D)=8/33}}}
DG-{{{P(D,G)}}}=??
Remember also that the sum of the probability for all of the events must be 1.
So you can solve this problem in two ways, or use the other way to check your work.