Question 359687
You didn't use parentheses to segregate numerators and denominators but here's my best guess.
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{{{(u+5)/(8v^2u^2)-(u-6v)/(8v^2u^2)=(u+5-(u-6v))/(8v^2u^2)}}}
{{{(u+5)/(8v^2u^2)-(u-6v)/(8v^2u^2)=(u+5-u+6v)/(8v^2u^2)}}}
{{{highlight((u+5)/(8v^2u^2)-(u-6v)/(8v^2u^2)=(6v+5)/(8v^2u^2))}}}