Question 359642
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Hi,
Let x be the low-rate of one hose.  Then 3x would the low-rate of the other
question states following (using "in 1hr's time" as the equalizer)
{{{(1/x) + (1/3x) = (1/3hr)}}}
Multiplying both sides of the equation by 3x so as all denominators are 1
3 + 1 = x
4 = x
on hose can fill the tank in 4 hrs the other in (3*4) or 12 hrs
checking our answer
1/4  + 1/12 =  4/12 =1/3