Question 359630
{{{(y-3)/2 = 8/(y-3)}}}
{{{(y-3)^2=16}}}
{{{y^2-6y+9=16}}}
{{{y^2-6y-7=0}}}
{{{(y-7)(y+1)=0}}}
Two solutions:
{{{y-7=0}}}
{{{highlight(y=7)}}}
.
.
.
{{{y+1=0}}}
{{{highlight(y=-1)}}}