Question 359560
Each number has an equal probability of being chosen.
So when you spin 950 times, on average, you would get each number 50 times.
Since {{{50*19=950}}}
So the random variable would look like,
({{{x}}},{{{P(x)}}})
({{{1}}},{{{50/950}}})
({{{2}}},{{{50/950}}})
({{{3}}},{{{50/950}}})
.
.
.
({{{18}}},{{{50/950}}})
({{{19}}},{{{50/950}}})