Question 359440
That would only work if their product equals 5 simultaneously.
So when one factor equals 5, the other equals 1.
When {{{x+3=5}}}, {{{x=2}}}, but {{{2(2)-1=4}}}, so then the product equals {{{5*4=20}} and not {{{5}}} as expected.
When {{{2x-1=5}}}, {{{x=3}}}, but {{{3+3=6}}}, so then  the product equals {{{5*6=30}}} and not {{{5}}} as expected.