Question 359408
Graph the equation by plotting points.  
<pre>
y = -5

Since the variable x does not appear in the equation,
x can be any number we choose.  However the value of
y can only be -5.

So to make a table of values of points, we don't need
to do any calculations, but just pick some arbitrary
values for the x-coordinate, the variable that does not 
appear in the equation, and use -5 for the y-coordinate:

  x  |  y  |  (x,y)
 -7  | -5  | (-7,-5)
 -4  | -5  | (-4,-5)
  1  | -5  |  (1,-5)
  5  | -5  |  (5,-5)
  8  | -5  |  (8,-5)

So we plot those 5 points:

{{{drawing(400,400,-10,10,-10,10,

graph(400,400,-10,10,-10,10),


line(-7+.1,-5,-7-.1,-5),line(-7,-5+.1,-7,-5-.1),line(-7+.1,-5+.1,-7-.1,-5-.1),line(-7+.1,-5-.1,-7-.1,-5+.1), locate(-7,-5,"(-7,-5)"),

line(-4+.1,-5,-4-.1,-5),line(-4,-5+.1,-4,-5-.1),line(-4+.1,-5+.1,-4-.1,-5-.1),line(-4+.1,-5-.1,-4-.1,-5+.1), locate(-4,-5,"(-4,-5)"),

line(1+.1,-5,1-.1,-5),line(1,-5+.1,1,-5-.1),line(1+.1,-5+.1,1-.1,-5-.1),line(1+.1,-5-.1,1-.1,-5+.1), locate(1,-5,"(1,-5)"),

line(5+.1,-5,5-.1,-5),line(5,-5+.1,5,-5-.1),line(5+.1,-5+.1,5-.1,-5-.1),line(5+.1,-5-.1,5-.1,-5+.1), locate(5,-5,"(5,-5)"),

line(8+.1,-5,8-.1,-5),line(8,-5+.1,8,-5-.1),line(8+.1,-5+.1,8-.1,-5-.1),line(8+.1,-5-.1,8-.1,-5+.1), locate(8,-5,"(8,-5)")
 )}}}

Now we just draw a line through all those points (I'll draw it
in green):

{{{drawing(400,400,-10,10,-10,10,

graph(400,400,-10,10,-10,10),


line(-7+.1,-5,-7-.1,-5),line(-7,-5+.1,-7,-5-.1),line(-7+.1,-5+.1,-7-.1,-5-.1),line(-7+.1,-5-.1,-7-.1,-5+.1), locate(-7,-5,"(-7,-5)"),

line(-4+.1,-5,-4-.1,-5),line(-4,-5+.1,-4,-5-.1),line(-4+.1,-5+.1,-4-.1,-5-.1),line(-4+.1,-5-.1,-4-.1,-5+.1), locate(-4,-5,"(-4,-5)"),

line(1+.1,-5,1-.1,-5),line(1,-5+.1,1,-5-.1),line(1+.1,-5+.1,1-.1,-5-.1),line(1+.1,-5-.1,1-.1,-5+.1), locate(1,-5,"(1,-5)"),

line(5+.1,-5,5-.1,-5),line(5,-5+.1,5,-5-.1),line(5+.1,-5+.1,5-.1,-5-.1),line(5+.1,-5-.1,5-.1,-5+.1), locate(5,-5,"(5,-5)"),

line(8+.1,-5,8-.1,-5),line(8,-5+.1,8,-5-.1),line(8+.1,-5+.1,8-.1,-5-.1),line(8+.1,-5-.1,8-.1,-5+.1), locate(8,-5,"(8,-5)"), green(line(-12,-5,12,-5))
 )}}}

So as you see, it's horizontal, not vertical.

Edwin</pre>