Question 359131
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Recall the Difference of Two Squares factorization:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^2\ -\ b^2\ =\ (a\ +\ b)(a\ -\ b)]


Let *[tex \Large a^2\ =\ 36w^2] and *[tex \Large b^2\ =\ 121]


Then *[tex \Large a\ =\ 6w] and *[tex \Large b\ =\ 11]


Just follow the pattern.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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