Question 359113
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I just did this one for you, but here it is again in case you missed it.


You can't do <i>exactly</i> what you ask.  You asked for <i><b>the</b></i> equation for a line, but since there are an infinite number of equivalent representations of any given line in equation form, the best you can do is write <i><b>an</b></i> equation of the line that fits the given criteria.  Equation is spelled with a "t" not an "s"


Use the slope formula to calculate the slope of the line that contains *[tex \Large (1,2)] and *[tex \Large (3,8)].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \frac{y_1\ -\ y_2}{x_1\ -\ x_2} ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Since


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


Which is to say parallel lines have identical slopes, by calculating the slope of the line through *[tex \Large (1,2)] and *[tex \Large (3,8)], you now know the slope of the desired line.


Use the point-slope form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point *[tex \Large (-2,4)] and *[tex \Large m] is the calculated slope.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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