Question 359013

Use a common denominator, {{{x^2-9=(x+3)(x-3)}}}
{{{(x(x+3))/((x-3)(x+3))+((2-x^2))/(x^2-9)=(x-3)/((x-3)(x+3))}}}
{{{(x(x+3)+2-x^2)-(x-3))/((x-3)(x+3))=0}}}
{{{(x^2+3x+2-x^2-x+3)/((x-3)(x+3))=0}}}
{{{(2x+5)/((x-3)(x+3))=0}}}
This can only occur when the numerator equals zero.
{{{2x+5=0}}}
{{{2x=-5}}}
{{{highlight(x=-5/2)}}}