Question 359071
let {{{mu}}} = average rate per minute 
let X=number of emails received
You need to realize that the situation you are describing follows a Poisson distribution
P(x=a)={{{mu^a*e^(-mu)/a!}}}
==
given
{{{mu=4}}}

{{{P(x>=2)=1-P(x<=1)=1-P(x=0)-P(x=1)}}}
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P(x=0)={{{4^0*e^(-4)/0!=e^(-4)=0.01832}}}
P(x=1)={{{4^1*e^(-4)/1!=4*e^(-4)=0.07326}}}
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can you finish this?