Question 359051

To find the x-intercept, set {{{y=0}}} and solve for {{{x}}}.
{{{x^2-9=0}}}
{{{x^2=9}}}
{{{x=0 +- 3}}}
({{{-3}}},{{{0}}}) and ({{{3}}},{{{0}}})
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To find the y-intercept, set {{{x=0}}} and solve for {{{y}}}.
{{{y=x^2-9}}}
{{{y=-9}}}
({{{0}}},{{{-9}}})
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{{{drawing(300,300,-10,10,-10,10,circle(0,-9,0.4),circle(-3,0,0.4),circle(3,0,0.4),grid(1),graph(300,300,-10,10,-10,10,x^2-9))}}}