Question 358802
Use the quadratic formula,
{{{x^2-4x+6=0}}}
{{{a=1}}}
{{{b=-4}}}
{{{c=6}}}
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{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (4 +- sqrt( (-4)^2-4*1*6 ))/(2*1) }}}
{{{x = (4 +- sqrt( 16-24))/2 }}}
{{{x = (4 +- sqrt( -8))/2 }}}
{{{x = (4 +- 2sqrt( -2))/2 }}}
{{{highlight(x = 2 +- sqrt( 2)i )}}} where {{{i=sqrt(-1)}}}
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Now follow the same procedure for the second equation.