Question 359027
{{{mu}}} is the mean.
{{{mu=sum(x*P(x),i=1,5)=1(0.6)+2(0.1)+3(0.1)+4(0.1)+5(0.1)}}}
{{{mu=highlight(2)}}}
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Calculate the variance first, then {{{sigma}}}.
{{{VAR=sum((x-mu)^2*P(x),i=1,5)=(1-2)^2(0.6)+(2-2)^2(0.1)+(3-2)^2(0.1)+(4-2)^2(0.1)+(5-2)^2(0.1)}}}
{{{VAR=(0.6)+(0.1)+4(0.1)+9(0.1)}}}
{{{VAR=2}}}
{{{sigma=sqrt(VAR)}}}
{{{sigma=sqrt(2)}}}
{{{highlight(sigma=1.414)}}}