Question 359001
{{{49=47.5*(2.7182)^(0.07*x)}}}
{{{(2.7182)^(0.07*x)=49/47.5}}}
{{{(2.7182)^(0.07*x)=49/47.5}}}
{{{0.07x=log(2.7182,(49/47.5))}}}
{{{x=(1/0.07)*log(2.7182,(49/47.5))}}}
{{{highlight(x=(1/0.07)*(log((49/47.5))/log((2.7182))))}}} or approximately,
{{{x=0.444165}}}