Question 358967
1)find three  consecutive odd integers such that three times the first is 83 more than the sum of the second and the third 
let the integers be x,x+2,x+4
3x= 83+x+2+x+4
3x=89+2x
3x-2x=89
x= 89
...
89,91,93

2)find four consecutive integers such that the sum of the last three integers is 20 more than two times the first 
let the integers be x,x+1,x+2,x+3
...
x+1+x+2+x+3=2x+20
3x+6=2x+20
3x-2x=20-6
x=14
...
14,15,16,17
...
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