Question 358653
1.{{{2x-y=16}}}
2.{{{2x+3y=-8}}}
Subtract eq. 2 from eq. 1,
{{{2x-y-2x-3y=16-(-8)}}}
{{{-4y=24}}}
{{{highlight(y=-6)}}}
Then from eq. 1,
{{{2x+6=16}}}
{{{2x=10}}}
{{{highlight(x=5)}}}
One unique solution, consistent and independent.