Question 358922
let one son's age =x
the other son's age =3x
...
father's age = 4(x+3x)
=16x
..
after 24 years
son x+24
other son 3x+24
Father = 16x+24
...
x+24+3x+24=16x+24-12
4x+48=16x+12
16x-4x=48-12
12x=36
/12
x=3 years one son's age
second son's age = 3x= 9 years
father's age = 16x = 48 years
...
m.ananth@hotmail.ca