<PRE><B>Question 358917</B>
the AVERAGE weight of the top 5 fish caught in the tournament was 12.3 lbs. The second fish weighed 12.8 lbs. the third fish weighed 12.6 lbs, the fourth fish weighed 11.8lbs and the 5th fish weighed 9.7 lbs. What was the weight of the heaviest fish?
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Total weight of the 5 fish is 5*12.3 = 61.5 lbs.
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wt of 1st fish = x
wt of 2nd fish = 12.8 lbs
wt of 3rd fish = 12.6 lbs
wt of 4th fish = 11.8 lbs
wt of 5th fish =  9.7 lbs
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Solve: x + sum of 4 fish = 61.5 lbs
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x + 46.9 = 61.5
x = 14.6 lbs.
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The heaviest fish was 14.6 lbs.
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Cheers,
Stan H.</PRE>