Question 358799
log(base3)(81xy)^8. I have to write it out. so far i have: 8log(base3)x+ 8log(base3)+ 8log(base3)81. is this correct?
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log(base3)(81xy)^8
= {{{log(3,3^32x^8y^8)}}}
= {{{32 + log(3,x^8y^8)}}}
= {{{32 + 8log(3,x) + 8log(3,y)}}}
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Your answer was correct except you left out the y, and you didn't use the fact that 81 = 3^4.
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Use log(3,x) with the 3 braces { } for legibility.