Question 358712
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The way you rendered your function, the questions asked don't make any sense.  Hence, I'm going to presume that you really meant:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ \frac{1}{5}\left(x\ +\ 8\right)^2\ +\ 2]


instead of what you actually wrote which was:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ \frac{1}{5\left(x\ +\ 8\right)^2}\ +\ 2]


Your function is in vertex form, *[tex \Large \rho(x)\ =\ a\left(x\ -\ h\right)^2\ +\ k], which has a vertex at *[tex \Large (h, k)], an axis of symmetry at *[tex \Large x\ =\ h], a minimum or maximum value equal to the function value at the vertex, and the vertex is a maximum when *[tex \Large a\ <\ 0] or a minimum when *[tex \Large a\ >\ 0]


Hint:  Re-write your function thusly:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ \frac{1}{5}\left(x\ -\ (-8)\right)^2\ +\ 2]


{{{drawing(
500, 500, -19, 1, -1, 19,
grid(1),
graph(
500, 500, -19, 1, -1, 19,
(1/5)(x+8)^2+2))}}}


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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