Question 358607
I'm confused too. Please use parentheses.
Here's my guess.
{{{((64b^2)/(2b^2-4b+2))*((2b-2)/(8b))=(8b/(2(b^2-2b+1)))*((2(b-1))/1)}}}
      {{{((64b^2)/(2b^2-4b+2))*((2b-2)/(8b))=(8b/((b-1)^2))*(((b-1))/1)}}}
{{{((64b^2)/(2b^2-4b+2))*((2b-2)/(8b))=highlight((8b)/(b-1))}}}