Question 358561
{{{ 6x^4-19x^2+15=0 }}}
{{{(3x^2-5)(2x^2-3)=0}}}
Four solutions:
{{{3x^2-5=0}}}
{{{3x^2=5}}}
{{{x^2=5/3}}}
{{{x=0 +- sqrt(5/3)}}}
{{{highlight(x=0 +- sqrt(15)/3)}}}
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.
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{{{2x^2-3=0}}}
{{{2x^2=3}}}
{{{x^2=3/2}}}
{{{x=0 +- sqrt(3/2)}}}
{{{highlight(x=0 +- sqrt(6)/2)}}}