Question 358508
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Hi,

Note: The general vertex form of a parabola, {{{y=a(x-h)^2 +k}}} (h,k) is the vertex

completing the square to put into the vertex form of a parabola
y = x^2 - 3x -4
y = x^2 - 3x + 9/4 - 9/4 -4
vertex form is:
y =1*(x - 3/2)^2 - 25/4
Vertex is (3/2, - 25/4)  a>0 Therefore parabola opens upward and vertex is the Minimum
y intercept is Pt(0,-4)
{{{graph( 300, 300,-10,10,-10,10,x^2-3x-4) }}}