Question 358506
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Hi
y = 4x^2
Note: general vertex form of a parabola, {{{y=a(x-h)^2 +k}}}   (h,k) is the vertex
y = 4x^2 tells us (0,0) is the vertex.  a >0 therefore parabola opens upward
and the vertex pt(0,0)is the Minimum 
{{{graph( 300, 300,-10,10,-10,10,4x^2) }}}