Question 358464
<pre>
Because when written with a radical <font face = "symbol">Ö</font> a square
root or a 4th root {{{root(4," ")}}}, or a 6th root {{{root(6," ")}}}, 8th root
{{{root(8," ")}}}, or any root with an EVEN index can never represent a negative
number <i><font size = 1>(that's not true with odd index roots)</i></font>.

Therefore your equation

{{{sqrt(3x)}}}{{{""=""}}}{{{-6}}}

has a square root written with a radical on the left, which means that
the left side is NOT negative.  Yet it is equal to a negative number on
the right,  which means it can have no real solution.

Edwin</pre>