Question 358404


Let width is x, then length = 2x+5

 x(2x+5) = 52

 => 2x^2 +5x -52 = 0

 => 2x^2 +13x - 8x -52 = 0

 =>  x(2x + 13) -4(2x + 13) = 0

 => (x-4) (2x+13) = 0

hence x =4, 2x+5 = 13



dimensions are 4 and 13.