Question 358273
5x      6x+18
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x^2-9  15x^3

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Cancel the 5 and the x:
Factor where you can:
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1/[(x-3)(x+3)] * [6(x+3)]/3x^2
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Cancel the (x+3) and the 3:
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1/(x-3)* (2/x^2)
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= 2/[x^2(x-3)]
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Cheers,
Stan H.
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