Question 357976
{{{((-8a^4b^7)/(16a^5b^6))^5 =((-8/16)a^(4-5)b^(7-6))^5}}}

{{{((-8a^4b^7)/(16a^5b^6))^5=((-1/2)a^(-1)b^(1))^5}}}
{{{((-8a^4b^7)/(16a^5b^6))^5=(-b/(2a))^5}}}
{{{((-8a^4b^7)/(16a^5b^6))^5=highlight(-(b^5)/(32a^5))}}}