Question 357947
{{{((-3a^4b^8)/(6a^3b^12))^4=(-3a^4b^8)^4/(6a^3b^12)^4}}}
{{{((-3a^4b^8)/(6a^3b^12))^4=(81a^16b^32)/(1296a^12b^48)}}}
{{{((-3a^4b^8)/(6a^3b^12))^4=(1/16)a^(16-12)b^(32-48)}}}
{{{((-3a^4b^8)/(6a^3b^12))^4=(1/16)a^(4)b^(-16)}}}
{{{((-3a^4b^8)/(6a^3b^12))^4=highlight(a^(4)/(16b^(16)))}}}