Question 357928
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Hi,
{{{x^2/3+7x^1/3+12=0}}}
Multiplying thru with 3 to clear the denominators
{{{x^2 +7x^1 + 36 = 0}}}
using quadratic formula o solve
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
there are no real solutions
{{{x = (-7 +- sqrt( -95 ))/(2) }}} 
Solutions involving imaginary numbers would be as follows:
{{{x = (-7 +- i*sqrt( 95 ))/(2) }}}