Question 357821
{{{(2-7i)/(1-6i) + (3-5i)/(1-6i)=(2-7i+3-5i)/(1-6i)}}}
{{{(2-7i)/(1-6i) + (3-5i)/(1-6i)=(5-12i)/(1-6i)}}}
{{{(2-7i)/(1-6i) + (3-5i)/(1-6i)=((5-12i)/(1-6i))*((1+6i)/(1+6i))}}}
{{{(2-7i)/(1-6i) + (3-5i)/(1-6i)=(5+30i-12i-72i^2)/(1+6i-6i-36i^2)}}}
{{{(2-7i)/(1-6i) + (3-5i)/(1-6i)=(77+18i)/(37)}}}
{{{(2-7i)/(1-6i) + (3-5i)/(1-6i)=highlight((77/37)+(18/37)i)}}}