Question 357882
The probability of one woman making a purchase is equal to the probability of the first purchasing, second not plus the probability of the second purchasing, the first not plus the probability of both purchasing.
{{{P=(0.7)(0.3)+(0.3)(0.7)+(0.7)(0.7)}}}
{{{P=2(0.21)+0.49}}}
{{{P=0.42+0.49}}}
{{{P=0.91}}}
We could have also worked it backwards.
The probability also that at least 1 women purchased plus the probability that neither purchased equals 1.
{{{P(p)+P(np)=1}}}
{{{P(np)=(0.3)(0.3)=0.09}}}
{{{P(p)=1-P(np)}}}
{{{P(p)=1-0.09}}}
{{{P(p)=0.91}}}